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Dear Chris,
Thank you for your reply.
The unit vector is required, I will endeavour to expand on the
method presented and to add some thoughts on the topic.
With a 2D vector a given by (x,y) and the axes by i(1,0) and
j(0,1). The angle between a and the positive i axis is given by:
cos(theta1) = a.i/||a||.||i|| = x/||a||
Similarly, The angle between a and the positive j axis is given by:
sin(theta2) = a.j/||a||.||i|| = y/||a||
with ||a|| the length of a, therefore
theta1 = acos(x/||a||)
theta2 = asin(y/||a||)
With 0
Thank you for your reply.
The unit vector is required, I will endeavour to expand on the
method presented and to add some thoughts on the topic.
With a 2D vector a given by (x,y) and the axes by i(1,0) and
j(0,1). The angle between a and the positive i axis is given by:
cos(theta1) = a.i/||a||.||i|| = x/||a||
Similarly, The angle between a and the positive j axis is given by:
sin(theta2) = a.j/||a||.||i|| = y/||a||
with ||a|| the length of a, therefore
theta1 = acos(x/||a||)
theta2 = asin(y/||a||)
With 0